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Sep 24, 2020 · Number of images formed by two plane mirrors inclined at an angle of $\theta$ is given by $$\frac{360}{\theta} -1 $$ What I think: Inclined mirror forms images in the circle and one image lies in one sector. No of images = Number of sectors= $\frac{360}{\theta}$ And $1$ is subtracted from $\frac{360}{\theta}$ because a sector is occupied by the ...
Feb 3, 2017 · In the same vein as you, let us consider the pencil of planes defined by the two planes (the set of planes sharing the same intersection line as the initial plane and the mirror plane), i.e., the set of planes $(\Pi_k)$ with equations:
Mirror a line over a plane. 1. How to verify finished problem with laser reflection on a mirror (plane mirror) 0. Reflection in a plane . 1. The Matrix of a reflecti ...
So, the initial situation is $\vec{a}$ pointing toward a plane. Then we have the normal $\vec{n}$ of unit lenght and we would like to find $\vec{b}$ So, the first step is using the dot product to get a vertical vector that will be used in step 2.
Is there a shorthand trick to figure out which plane is being mirrored about? linear-algebra; matrices; Share. Cite. Follow edited Nov 2, 2014 at 15:02. Ortix92. as ...
Jan 14, 2016 · Here are diagrams of what's going on: You can work out how long the line at the bottom is by comparing the big triangle with the little triangle.
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$\begingroup$ In the first place, a plane is determined by three points (not on a line). Unless your points are given numerically and are not lying on a plane anyway, you may discard the point $(x_4,y_4,z_4)$. When the four points are given numerically there arises the question of the "optimal plane" corresponding to these points. $\endgroup$
Nov 29, 2020 · in fact, one can "mirror" any geometrical object with respect to a circle in 2D or a sphere in 3D using a transformation called "inversion" which is described here. The mirroring property can be seen on the example of the fish "reflected" with respect to his bowl. A circle is in general reflected into a circle. For extended information and references, see
Oct 14, 2017 · You have made a computation mistake, as has been pointed out in the other posts. Your idea is nonetheless true: if you have two direction vectors lying in the plane, then their cross product will result in a vector orthogonal to both these vectors, i.e. normal to the plane.
