Search results
- Dictionaryfunction/ˈfʌŋ(k)ʃn/
noun
- 1. an activity that is natural to or the purpose of a person or thing: "bridges perform the function of providing access across water" Similar
- 2. a relation or expression involving one or more variables: "the function (bx + c)"
verb
- 1. work or operate in a proper or particular way: "her liver is functioning normally" Similar Opposite
Powered by Oxford Dictionaries
Souler. 11 1 1 3. 2. use := instead of = and read about Set and SetDelayed. – eldo. Oct 18, 2015 at 17:53. 3. Note that if you do not include a space between x and y in xy, the latter will be considered as an independent variable of name xy. This being said, defining f[x_, y_] = (y/x) + x y and asking for f[1, 2] works fine for me and returns 4.
$\begingroup$ @jVincent no, I meant true function, not pure. true function in the mathematical sense. it only acts on its input via arguments, and has local variables and has no side effects other than its return value. A true function does not even allow passing argument by reference. Ada functions used to be true, until Ada 2012 where they ...
This has the attribute , which prevents you from assigning any definition to it. Attributes@O. Out[1]= {Protected, ReadProtected} However, to answer the question in your title, here are a few simple ways in which you can use a function inside another function:
Mar 1, 2015 · 1. This works: f[u_, x_] := D[u, x] + a[x] u. By way of explanation, everything is an expression, and there is nothing particularly special about functions. You and I know that this definition doesn't have lot of meaning for objects "u" that aren't functions, but Mathematica doesn't need to know that u is a function.
Sorted by: You cannot make definitions with patterns on the left-hand side in the first argument of a scoping construct (such as Module). You need do that in the body of the Module. You should also use a different symbol for the internal function parameter. norm[x_] :=. Module[{fun1, fun2}, fun1[p_] := p^2 + p - 1;
TrueQ[OptionValue["Quiet"]], Message[AmakeB::Function, fn] ]; ] Now the function that is created is not returned via a Return from the Module but is added to the Global context. One of the advantages to me is that now I can define an arbitrarily complex function. Usage: AmakeB[1, 1] Returns nothing but now the function Fun exists:
Usually, we define a function as . F[x_] := x + 10 where the right-hand side is an expression. Now, I would like define a function where the right-hand side is the s ...
Sep 12, 2016 · First argument of f function is first element of sequence, second argument is standard sequence specification, so {n} will give n-th element of sequence, {min, max} will give list containing elements from min to max, max will give elements from 1 to max.
So again, yes you can define a function that has: any number of arguments, any number of local variables, routines that set local variables, and; return any, all, or any combination of the local variables. Note one can also define local functions inside a function then use them just as you would any other. A simple if kind of silly example follows:
Feb 4, 2018 · One other possibility is to simply chain the functions together: f[x_] := Table[#[[i,i]] + #[[i+1,i+1]], {i,1,2 N - 1, 2}] & [Msum[x]] This constructs a function which takes x as the argument, calculates Msum[x], and passes it inside into a function which calculates the requested Table. At this point it's equally simple to just create f such ...
