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May 20, 2016 · Surds-Factorising or 'proving that x =' Circle Theorems-Usually comes up as a simple 3 marker at the beginning or a 6marker on something like alt segment theory Ratio and Proportion-Pretty much a standard thing to expect 'daisy has 100g of cake mix, butter and flour in ratio 3:6' Cumulative Freq-Usually a multiple (a, b, c) part question, requiring you to fill in a table and then complete a ...
I have here a past Unit 2 Edexcel Practice paper, anyone who's doing the exam can use it for revision. TA and TB are tangents to the circle. CA = CB. Angle ATB = 2x°. Prove that angle ACB = (90 – x)°. Could anyone explain in detail how you managed to get the answer, because right now I'm slightly confused. Thankyou.
So 180 - 116 = 64 (the total of the other two angles must equal this) 64 / 2 = 32. Therefore the answer is 32 degrees. Hope that is some help to get you going! Always remember your isosceles rule - 2 equal sides, 2 equal angles (this comes in handy with a lot of questions!!) And total angles in a circle = 180 degrees.
What good websites are there for a comprehensive guide to all circle theorem required for AS. 0 Report. Reply. Reply 1. 9 years ago. brianeverit . 9. Original post b ...
Nov 7, 2023 · Circle theorem; Watch . 10 months ago. Circle theorem ... point A B and C form an equilateral triangle inside the circle if triangle ABC isn't an eq ...
Maths Circle theorems HELP PLEASE. Angle BOC = 160 degrees because the angle at the centre of the circle is 2x that of the angle at the circumference. I can give you all the clues that you can use to solve the questions in (a); you need to figure out the actual solutions by yourself. • The letter O always indicates the centre of the circle.
Therefore, due to alternate segment theorem: <QRT = <SUT = 72. Therefore, <TSU = <SUT. Thus, ST = UT, so TSU is an isosceles triangle! 1 Report. Reply 4. 7 years ago ...
EDO=90 degrees because tangent meets the radius at 90 degrees. OBD is an isosceles triangle so OBD = 25 because base angles on a triangle are equa DOB = 130˚ 180- (25*2)=130. DAB=65˚ because angles subtended at the arc is twice the angle subtended at the circumference so 130÷2=65˚. this is what i have done and it has only given me 2 marks ...
14. this is how i did it... angle BDA = 32 , because of angle in opposite segment rule. angle DBC = 32 , because of alternate ('Z') angles. angle BDC = 32 , because triangle BCD is isoceles. angle BCD = 116 , because angles in a triangle add up to 180. therefore angle BAD = 64 , because opposite angles in a cyclic quad. add up to 180.
The two other angles in the triangle (in the circle) are 68 degrees each. The two triangle form a kite. Where a tangent touches a circle it's at a 90 degree angle. So 90-68 = 22. 22*2 = 44. 180-44 = 136 degrees. That's what I think the answer is, seems a little difficult for GCSE but meh.
